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Appendix D. Problems and selected solutions

Problem 1 — Electron versus proton mass #

Using mpc2=938.27208943 MeVm_pc^2=938.27208943\,\mathrm{MeV} and mec2=0.51099895069 MeVm_ec^2=0.51099895069\,\mathrm{MeV}, calculate mp/mem_p/m_e and compare with the CODATA ratio.

Solution.

mpme=938.272089430.51099895069≈1836.15267,\frac{m_p}{m_e} =\frac{938.27208943}{0.51099895069} \approx1836.15267,

consistent with the CODATA value within the rounding used here. CODATA recommended values of the fundamental physical constants: 2022 (2024)

Problem 2 — Photon energy #

Find the energy of a 500 nm500\,\mathrm{nm} photon.

Solution.

E=hcλ≈1239.841984 eV nm500 nm≈2.48 eV.E=\frac{hc}{\lambda} \approx\frac{1239.841984\,\mathrm{eV\,nm}}{500\,\mathrm{nm}} \approx2.48\,\mathrm{eV}.

Problem 3 — Weak length scale #

Estimate ℏc/MWc2\hbar c/M_Wc^2 using MW≈80.4 GeVM_W\approx80.4\,\mathrm{GeV}.

Solution.

ℓW∼0.1973 GeV fm80.4 GeV≈2.45×10−3 fm=2.45×10−18 m.\ell_W\sim\frac{0.1973\,\mathrm{GeV\,fm}}{80.4\,\mathrm{GeV}} \approx2.45\times10^{-3}\,\mathrm{fm} =2.45\times10^{-18}\,\mathrm m.

This is only an order-of-magnitude range estimate; weak amplitudes are computed from propagators, not from a literal finite flight path of a virtual WW boson.

Problem 4 — Higgs Yukawa coupling of the electron #

Estimate the electron Yukawa coupling using me=yev/2m_e=y_ev/\sqrt2 and v=246.22 GeVv=246.22\,\mathrm{GeV}.

Solution.

ye=2mev≈2.94×10−6.y_e=\frac{\sqrt2m_e}{v} \approx2.94\times10^{-6}.

The smallness of this dimensionless number is part of the unexplained flavor hierarchy.

Problem 5 — QCD crossover temperature in kelvin #

Use kB=8.617333262…×10−5 eV/Kk_B=8.617333262\ldots\times10^{-5}\,\mathrm{eV/K} to convert 156.5 MeV156.5\,\mathrm{MeV} to kelvin.

Solution.

T≈156.5×106 eV8.617333262×10−5 eV/K≈1.82×1012 K.T\approx\frac{156.5\times10^6\,\mathrm{eV}} {8.617333262\times10^{-5}\,\mathrm{eV/K}} \approx1.82\times10^{12}\,\mathrm K.

CODATA recommended values of the fundamental physical constants: 2022 (2024) · Chiral crossover in QCD at zero and non-zero chemical potentials (2019)

Problem 6 — Why a photon has no rest frame #

Show that the Lorentz factor diverges as v→cv\to c.

Solution. Since 1−v2/c2→0+1-v^2/c^2\to0^+,

γ=(1−v2/c2)−1/2→∞.\gamma=(1-v^2/c^2)^{-1/2}\to\infty.

A finite Lorentz boost cannot transform an inertial observer into a lightlike rest frame.

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